PHYSICS THEORY NOW [AVAILABLE] ENTER FAST

WE ARE  LATE BCOS WE WANT TO ENSURE ITS CORRECT....

(1a)
F= Force, m= Mass, a= Acceleration
F is directly proportional to (m)
F/a=ma/a
m=F/a (N/m)

(1b)
Dimensionally analysis
for m=M
since F= MLT -2
a=LT -2
hence, F/a=MLT -2/LT -2
:. Dimension for m = Dimension for F/a which is M
This implies that the equation is dimensionally correct
(2)
U=20m/s
S=125m
t=?
g=10m/s -2
S=ut + i/2at 2
125= 20t + 1/2(10)t 2
125=20t + 5t 2
5t 2 + 20t-125=0
Dividing through by 5
5t 2/5 + 20t/5 -125/5 =0/5
t 2 + 4t - 25=0
solving the equation quadratically, using general
method
t= -bt + sqrt(b 2)-4ac/2a
t= -bt - sqrt(b 2)-4ac/2a
a=1, b=4, c= -25
t= -4 + sqrt(4 2-4(1)(-125)/ 2*1
t= 4 + sqrt(16+500)/2
t= 4+ sqrt(416)/2
t= 4 + 20.4/2 or 4-20.4/2
t= 24.4/2 or -16.4/2
hence, t=12.25 or -8.25
so the time it takes the ball to reach the ground
(t)=12.25

NEW...
(3a)
i. The angle which the object makes with the horizontal line
ii. acceleration due to gravity

 (3b)
At maximum range tita= 45degree

(6) m= 9.1*10 -31kg
v=6.6*10 7m/s
wavelenght= ?
h=6.6*10 -34Js
wavelenght =h/meV
V= sqrt(2eV/me)
wavelenght= 6.6*10 -34/ (9.1*10 -34)*(6.6*10 -7)
=1/9*10 7
wavelenght= 0.11*10 7
wavelenght:(1.1*10 6)1electrovolt
1electrovolt = 1.6*10 -19
wavelenght:(1.1*10 -6) (1.6*10 -19)
=1.76*10 -13m

5a )  What material are use for making electrc bell 
1.Electromagnet

 2. Armature 

3. Spring

4. Armaturerod

5. Hammer

 6. Gong 


(7)
l1 =5.0*10^-2m=e1

l2=5.5*10^-2m=e2

l3= 6.5*10^-2m=e3

load(m1)=0.2N

m=ke
k=m/e
0.2/(5.5*10^-2 )-(5*10^-2) = m2/(6.5*10^-2)-(5.5*10^-2)

0.2/0.5=m2/1.0

0.5m2/0.5=0.2/0.5

m2= 0.4N

The additional load= 0.4N

NEW..(8a)
Free fall is that force that acts on every objects at a distance for example the earth exerts at force on a falling object and the gravitational field surrounds everybody that has mars


(8b)
The two conditions of equilibrium are:
-Concurrent Equilibrium the sum of vector forces through a point is zero.
-Coplanar equilibrium, the sum of forces in a plane is zero and the sum of the torques around the axis of the plane is zero.


(8c)
Escape velocity is defined as the velocity at which an object escape or surpass the effect of force of gravity


(8d)
Mass(m)=5kg
h=s=4m
g=10m/s
v=?
V power2= U 2 + 2gs
V power2 = 0 2 + 2*10*4
V power2= 0 + 80
V power2= 80
V= sqrt(80)
V=8.9m/s


(8e)
Total Mass= MT= 210kg
Frictional Force(F' (10/100 * 210 =21kg
g=10m/s power-2
Velocity(V)=1.2ms power-1


F-F'=mg


mv=ft


f=mv/t
(210 - 21)1.2/t=210


189*1.2/t=210

t=210/189*1.2=0.935


f=mv/t= (210 - 21)/0.93 * 2


f=189*2/0.93


f=175.77N


f=175.8N
KEEP REFRESHING MORE SOLUTION IS COMING..............................